Hello,

I am new to Umbraco and XSLT and your help is greatly appreciated.

I have a requirement such that the top level menu items might contain links to external sites. In order to implement this, I have created a document type called 'External Link' (with an alias of 'externalLink'). To display the top level navigation, below is the XSL snippet I am using.

The output is that the '<xsl:when test="string(./@nodeTypeAlias) = 'externalLink'">' is not executed even when the menu item is in fact associated with the 'External Link' doc type.

I am aware that the @nodeTypeAlias has been replaced with $currentPage/externalLink, but I am having difficulty using this with the XSL snippet below.

<div id="navigation">
<ul>
<li class="home">
<xsl:if test="$currentPage/@id = $currentPage/ancestor-or-self::* [@level=$level]/@id">
<xsl:attribute name="class">active</xsl:attribute>
</xsl:if>
<a href="/">Home</a>
</li>
<xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
<li>
<xsl:choose>
<xsl:when test="string(./@nodeTypeAlias) = 'externalLink'">
<a href="{./data [@alias='externalURL']}">
<span class="external"><xsl:value-of select="@nodeName"/></span>
</a>
</xsl:when>
<xsl:otherwise>
<xsl:if test="$currentPage/@id=current()/@id or current()/@id=$currentPage/ancestor-or-self::*/@id">
<xsl:attribute name="class">active</xsl:attribute>
</xsl:if>
<a class="navigation" href="{umbraco.library:NiceUrl(@id)}">
<span><xsl:value-of select="@nodeName"/></span>
</a>
</xsl:otherwise>
</xsl:choose>
</li>


</xsl:for-each>
</ul>
</div>

Thanks for your help.

Regards,
shwetha