get nodes sorted by property in for each loop - XSLT

Go to solution

Press Ctrl / CMD + C to copy this to your clipboard.

Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at

mfeola 117 posts 221 karma points

Oct 27, 2010 @ 21:18

Get Nodes sorted by property in for-each loop

XSLT

I am having an issue with the XSLT properties selection in the latest download of umbraco

here is my code:

<xsl:param name="currentPage"/>
<xsl:param name="root" select="$currentPage/ancestor-or-self::* [@level = '1']"/>
    
<xsl:template match="/">
  
<ul>
  <xsl:for-each select="$root//*[self::NewsPage and string(umbracoNaviHide) != '1']">
    <xsl:sort select="data[@alias = 'date']" order="descending"/>
    <xsl:if test="position() &lt; 10">
      <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName"/> 
          <xsl:value-of select="data[@alias = 'date']"/> 
          <xsl:value-of select="title"/> 
        </a>
      </li>
    </xsl:if>
  </xsl:for-each>  
</ul>

</xsl:template>

@nodeName displays fine but date and title do not display at all, as if they were empty but they aren't. I want to sort by the date field specifically and I tried the old way and the new way and neither seem to be working. Does anyone have any experience with the same issue?

Copy Link

mfeola 117 posts 221 karma points

Oct 27, 2010 @ 21:25

0

The code should get the latest NewPage documenttype in any folder and place it in a list. The latest item will be decided by the date field rather than @createDate because i had to import all these files so all the files are displayed by an arbitrary date of some time last week.

Copy Link

Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Oct 27, 2010 @ 21:33

Hi mfeola,

Try this:

<xsl:param name="currentPage" />
<xsl:param name="root" select="$currentPage/ancestor-or-self::*[@level = '1']" />

<xsl:template match="/">
<ul>
  <xsl:for-each select="$root//NewsPage[not(umbracoNaviHide = 1)]">
    <xsl:sort select="date" order="descending" />
    <xsl:if test="position() &lt; 10">
      <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName" /> 
          <xsl:value-of select="date" /> 
          <xsl:value-of select="pageTitle" /> 
        </a>
      </li>
    </xsl:if>
  </xsl:for-each>  
</ul>

</xsl:template>

The data[@alias = 'PROPERTY_ALIAS'] was the old way of doing it.

/Chriztian

Copy Link

mfeola 117 posts 221 karma points

Oct 27, 2010 @ 21:36

0

No change to the content and i am double checking to make sure the document type has a date and title property and it does. It's weird because I did other XSLTs before but they requested information from the currentnode and they had no issues.

Copy Link
mfeola 117 posts 221 karma points

Nov 03, 2010 @ 22:16

0

bah, i went ahead and just created a c# user control instead

i added the date and id to a datatable, sorted that, and displayed that information. it that works fine.

Copy Link
Paul Blair 466 posts 731 karma points

Nov 03, 2010 @ 23:10
0
You could try
```
<xsl:value-of select="./date" /> 
```
or
```
<xsl:value-of select="current()/date" /> 
```
failing that have a look at your /app_data/umbraco.config file to see how the values were stored
Copy Link
mfeola 117 posts 221 karma points

Nov 04, 2010 @ 19:17

0

i didnt know current was a function. i might try that in a future item and see if it works but for now i just did the datatable thing. i wish there was another way to mark this forum post as something other than solved... like not solvable or no longer an issue so i will just mark the last message as the solved one

Copy Link
is working on a reply...

Please Sign in or register to post replies