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  • Warren Caulton 2 posts 102 karma points
    Jul 20, 2017 @ 14:39
    Warren Caulton
    0

    Link To Media ver.7.6.4

    Using Umbraco And Getting Started
    Umbraco 7

    On my website I have a Link to media /media/1005/(myimage.jpg) Clicking on the link takes me to http://media/1005/(myimage.jpg) instead of http://(mywebsite)/media/1005/(my_image.jpg).

    I have a local version of Umbraco where I am integrating my own MVC controllers to use Progress Controls for my Data Display and Exports. I build in VS 2017, and publish the result to a File Folder on my 2008 IIS Web Server.

    How can synch the Media data between my Development Environment and my Production Environment?

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  • Alex Skrypnyk 6132 posts 23951 karma points MVP 7x admin c-trib
    Jul 20, 2017 @ 14:55
    Alex Skrypnyk
    0

    Hi Warren

    Can you show the code that renders an image?

    Thanks,

    Alex

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  • Warren Caulton 2 posts 102 karma points
    Jul 20, 2017 @ 16:20
    Warren Caulton
    100

    The Page code is:

    <div class="col-lg-5">
        <img style="padding-top:16px;" src="/Images/vintage_kohler_ad_upd.jpg" height="395">
    </div>

    The Template code is:

     <div class="col-lg-5">
        @{
            var typedMediaPickerSingle = Model.Content.GetPropertyValue<IPublishedContent>("bannerImage");
            if (typedMediaPickerSingle != null)
            {
                <img style="padding-top:16px;" src="@typedMediaPickerSingle.Url" alt="" height="395" />
            }
        } 
    </div>

    After updating the Template the page source now reads:

    <div class="col-lg-5">
                <img style="padding-top:16px;" src="/Kinsley2017/media/1006/kds_arrives_002.jpg" alt="" height="395">

    </div>

    The Template didn't get updated on the server. Your request for code cleared that up. Thanks

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  • Amir Khan 1282 posts 2739 karma points
    Jul 20, 2017 @ 18:15
    Amir Khan
    0

    So you're just wanting the domain in the request?

    If so you can just put this before your call to @typedMediaPickerSingle.Url: @HttpContext.Current.Request.Url.Host

    Hope this helps!

    Amir

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