getting url of page submitted from in xslt email workflow

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Mark 255 posts 612 karma points

Oct 21, 2014 @ 14:52

Contour

Contour 1.1.12

I can't see how to display the url from this xml:

<uformrecord>
    <state>Approved</state>
    <created>2014-10-21T11:47:01</created>
    <updated>2014-10-21T11:47:01</updated>
    <id>1e0b2f53-5338-48b7-b079-ea9d99ed6f17</id>
    <ip>88.7.46.126</ip>
    <pageid url="http://mysite.com/help/emailus/" name="Email us">5423</pageid>
    <memberkey email="" login=""></memberkey>
    <fields>
        <firstname record="1e0b2f53-5538-48b7-b073-ea9d99ed6f17" sortorder="1" pageindex="0" fieldsetindex="1">
            <key>dad0e688-4358-4b8f-a14b-f8e6a378afc3</key>
            <fieldKey>ba1bc39f-d9d5-4056-841c-382499068b78</fieldKey>
            <caption>First name*</caption>
            <datatype>String</datatype>
            <values><value><![CDATA[manny]]></value></values>
        </firstname>
    </fields>
</uformrecord>

Into this xslt file (see Url:...):

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:user="urn:my-scripts"
xmlns:umbraco.library="urn:umbraco.library"
exclude-result-prefixes="xsl msxsl user umbraco.library">

    <xsl:output method="html" media-type="text/html" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
    doctype-system="DTD/xhtml1-strict.dtd"
    cdata-section-elements="script style"
    indent="yes"
    encoding="utf-8"/>

    <xsl:param name="records" />

    <xsl:param name="id" />

    <xsl:template match="/">

    <p>
      This is the list of values it contained, you can turn this email off under workflows in Umbraco Contour
    </p>
    Url: <xsl:value-of select="umbraco.contour:GetRecord($id)/uformrecord/pageid/@url" />
    <xsl:for-each select="$records//fields/child::*">
        <br/>
        <strong>
            <xsl:value-of select="./caption"/>
        </strong>
        <br/>
        &#160;&#160;&#160;&#160;<xsl:value-of select=".//value"/>
    </xsl:for-each>

    <xsl:value-of select="."/>

    </xsl:template>

</xsl:stylesheet>

What am I missing / doing wrong? I can't find out what parameters contour passes into the XSLT, only examples online that contain $records

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Comment author was deleted

Oct 21, 2014 @ 14:55

To get an overview of the xml format check out this doc page http://our.umbraco.org/projects/umbraco-pro/contour/documentation/Developer/Working-with-Contour-data-in-XSLT/

The record holds a pageid, which is the id of the page the record was submitted on, you can then use the library method umbraco.library:NiceUrl to fetch the full url

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Mark 255 posts 612 karma points

Oct 22, 2014 @ 16:18
100
Hi @Tim

It turned out that the url parameter is already in the @records xml, it's an attribute of the pageid element, as per the xml in my original post. This must have been added in at some point. So all I had to do was replace this line in my XSLT file:
```
Url: <xsl:value-ofselect="umbraco.contour:GetRecord($id)/uformrecord/pageid/@url"/>
```
With this:
```
Url: <xsl:value-of select="$records/pageid/@url" />
```
I didn't need to access the umbraco.library at all. I assume it's safe to use the url attribute of the pageid element for this version of Contour. I'd appreciate it if you'd let me know otherwise.

Thanks!
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