setting the value of xslsort with a xslchoose - XSLT

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Probocop 51 posts 71 karma points

Jan 19, 2011 @ 13:31

0

Setting the value of xsl:sort with a xsl:choose?

XSLT

Hi, I'm using the same macro to list different types of content on different pages, one of the document types has a (mandatory) date field while the other doesn't.

What I'm trying to do is to check whether the first item has a date set, then use that to sort the list. If it doesn't then just use the @createDate.

My XSLT is currently as follows, but I get the error of xsl:sort has to be the first item inside the xsl:for-each.

<xsl:variable name="sortBy">
  <xsl:choose>
  <xsl:when test="contentDate > 0">
  <xsl:text>contentDate</xsl:text>
  </xsl:when>
  <xsl:otherwise>
  <xsl:text>@createDate</xsl:text>
  </xsl:otherwise>
  </xsl:choose>
  </xsl:variable>
  <xsl:sort select="$sortBy" order="descending" />

Can anybody think of a way of doing this?

Thanks!

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Lee Kelleher 4020 posts 15802 karma points MVP 13x admin c-trib

Jan 19, 2011 @ 14:07

Hi Probocop,

You can't use the variable's value directly in the sort's select - as that requires an XPath expression... so try this instead:

<xsl:variable name="sortBy">
    <xsl:choose>
        <xsl:when test="contentDate &gt; 0">
            <xsl:text>contentDate</xsl:text>
        </xsl:when>
        <xsl:otherwise>
            <xsl:text>@createDate</xsl:text>
        </xsl:otherwise>
    </xsl:choose>
</xsl:variable>
<xsl:apply-templates select="$currentPage">
    <xsl:sort select="contentDate[$sortBy = 'contentDate']" order="descending" />
    <xsl:sort select="@createDate[$sortBy = '@createDate']" order="descending" />
</xsl:apply-templates>

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Setting the value of xsl:sort with a xsl:choose?