Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at


  • Nigel Wilson 944 posts 2076 karma points
    May 20, 2015 @ 03:33
    Nigel Wilson
    0

    Help With Strongly Typed Views for Randomised Output

    Hi there

    Firstly, I am a NOOB to MVC using Umbraco.

    I have been tasked with outputting all nodes of a certain type in a random order, but for that random order to remain consistent for a 24 hour period. To date I have not found an Out-of-the-box way to achieve this with partial views. Does anyone know if this is possible?

     

    A solution I currently have in my head is :

     

    • create a model which only contains the properties I need for my page output, and add a property for a random number
    • within the custom controller create list of my custom model including the "randomisation" logic
    • within the view output the list created by 

     

    So I have scoured Google for some help and did find some resources but have been unable to get anything working as yet.

    My model is as follows:
    -----------------------------------
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Web;

    namespace umb724.Models
    {
        public class PersonModel
        {
            public int ID { get; set; }
            public string FirstName { get; set; }
            public string Surname { get; set; }
            public string URL { get; set; }
        }
    }

     

    My controller is as follows (pseudo entries purely in an attempt to wire up the MVC functionlity (random functionality will be included later):
    -----------------------------------

    using System.Collections.Generic;
    using System.Linq;
    using System.Web;
    using System.Web.Mvc;
    using umb724.Models;
    using Umbraco.Web.Mvc;

    namespace umb724.Controllers
    {
        public class PersonController : SurfaceController
        {
            public ActionResult Person()
            {
                List personModel = new List();                       

                PersonModel pm = new PersonModel();
                pm.FirstName = "Joe";
                pm.Surname = "Bloggs";
                pm.ID = 1234;
                personModel.Add(pm);

                PersonModel pm2 = new PersonModel();
                pm.FirstName = "John";
                pm.Surname = "Doe";
                pm.ID = 4321;
                personModel.Add(pm2);

                return View(personModel);
            }
        }
    }

     

    My View is as follows:
    -----------------------------------
    @model umb724.Models.PersonModel
    @{
        Layout = "~/Views/Master.cshtml";
    }

    @foreach (var item in Model.PersonListing)
    {

    @item.FirstName

     

    }

    ====================================

    Is anyone able to please assist and get me on track with respect to this ?

    Alternatively, can anyone sugest a simpler way to generate a random output that changes based on the day.

    Thanks, Nigel

  • Carl Jackson 139 posts 478 karma points
    May 22, 2015 @ 17:49
    Carl Jackson
    0

    I think your idea is there but you don't have a way of making it ocnsistant for 24 hours?

    How About using the built in umbraco ApplicationCache to cache for 24 hours?

    Entirely untested but something like.....

    public class PersonController : SurfaceController
    {
        public ActionResult Person()
        {
            var model = (List<PersonModel>) ApplicationContext.Current.ApplicationCache.RuntimeCache
                        .GetCacheItem("PersonModelCache", () =>
                        {
    
                            var personModel = new List<PersonModel>();                       
    
                            PersonModel pm = new PersonModel();
                            pm.FirstName = "Joe";
                            pm.Surname = "Bloggs";
                            pm.ID = 1234;
                            personModel.Add(pm);
    
                            PersonModel pm2 = new PersonModel();
                            pm.FirstName = "John";
                            pm.Surname = "Doe";
                            pm.ID = 4321;
                            personModel.Add(pm2);
                            return personModel
                        }, TimeSpan.FromMinutes(1440));
    
            return View(model);     
        }
    
    }
    
  • Nigel Wilson 944 posts 2076 karma points
    May 22, 2015 @ 20:07
    Nigel Wilson
    0

    Hi Carl

    Thanks for your great suggestion re caching - I had been wondering about this aspect so very timely.

    The randomisation aspect I haven't worked out yet but have some ideas in my head - my initial pain point is in getting the MVC part to work but you my have solved that in your code too.

    I will have a play with your suggestion and see how I get on.

    Again, thanks for the feedback - truly appreciated.

    Regards

    Nigel

Please Sign in or register to post replies

Write your reply to:

Draft