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Lee 1130 posts 3088 karma points

Jul 16, 2009 @ 16:35

XSLT

Probably pretty simple, but I have a doctype that has a propertie called ShowInFooter with a type of True/False. I'm trying to create a macro that would find any documents with this propertie set to true and display them in a list. I'm not getting any errors in my XSLT but its just not returning any documents when I know there is at least 1 with it set to true

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
   version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
 xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
   exclude-result-prefixes="msxml umbraco.library">
<xsl:output method="xml" omit-xml-declaration="yes" />
<xsl:param name="currentPage"/>
<xsl:template match="/">
<!-- The fun starts here -->
<ul id="footer">
<xsl:for-each select="$currentPage/ancestor::node/descendant-or-self::node">
<xsl:if test="$currentPage/node [string(data [@alias='ShowInFooter']) = '1']">
<li>
    <a href="{umbraco.library:NiceUrl(@id)}">
       <xsl:value-of select="@nodeName"/>
  </a>
</li>
</xsl:if>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>

Any help very appreciated as to where I am going wrong

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Sebastiaan Janssen 5045 posts 15477 karma points MVP admin hq

Jul 16, 2009 @ 16:38
0
Try this:
```
<xsl:if test="boolean($currentPage/data[@alias='ShowInFooter'])">
```
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Warren Buckley 2106 posts 4836 karma points MVP ∞ admin hq c-trib

Jul 16, 2009 @ 16:39
0
OK the first thing is to change your xsl:if $currentPage refers to the currentpage you are on and not the current item in the for-each loop.

So change
```
<xsl:if test="$currentPage/node [string(data [@alias='ShowInFooter']) = '1']">
```
to
```
<xsl:if test="current()/[string(data [@alias='ShowInFooter']) = '1']">
```
or which should do the same thing
```
<xsl:if test="[string(data [@alias='ShowInFooter']) = '1']">
```
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Lee 1130 posts 3088 karma points

Jul 16, 2009 @ 16:51
0
Thanks chaps, help very appreciated

@Warren - I tried both but get this error?
```
System.Xml.Xsl.XslLoadException: Unexpected token '[' in the expression.
```
@Sebastiaan - I added yours and it saved but still returns nothing? I have triple checked and the property is called 'ShowInFooter' and I have one document ticked as 'Yes' in the UI so I can't understand why it won't show!

Just checking my select does go all the way to the root and then back down? So it does check all documents?
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Ron Brouwer 273 posts 768 karma points

Jul 16, 2009 @ 16:59

0

<xsl:if test="$currentPage/node[string(data[@alias='ShowInFooter']) = '1']">

Check in data/umbraco.config if the data is saved as expected.

You can also add this xpath condition to the xsl:foreach for better performance.

Ron

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Sebastiaan Janssen 5045 posts 15477 karma points MVP admin hq

Jul 16, 2009 @ 17:01
1
Ah yes, I forgot you were already in a loop, so this should work a bit better:
```
<xsl:if test="boolean(data[@alias='ShowInFooter'])">
```
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Chris Dunn 210 posts 401 karma points

Jul 16, 2009 @ 17:04
1
Lee,

Remove the surrounding '[' and ']' from the condition in warren's 2nd example.
```
<xsl:if test="string(data [@alias='ShowInFooter']) = '1'">
```
-Chris
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Warren Buckley 2106 posts 4836 karma points MVP ∞ admin hq c-trib

Jul 16, 2009 @ 17:08
100
Sorry as Chris mentions it should be like this.
```
<xsl:if test="string(data [@alias='ShowInFooter']) = '1'">
```
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Warren Buckley 2106 posts 4836 karma points MVP ∞ admin hq c-trib

Jul 16, 2009 @ 17:09

0

Oops sorry didnt read properly. Chris had already given you the example. Im getting tired time to sign off for today !

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Lee 1130 posts 3088 karma points

Jul 16, 2009 @ 17:29

0

Man I thought this would be so easy! I really trying to stick with XSLT but I could do this with a lines of code in ASP.NET!! :(

Anyway... Still not working :(

@Ron -Tried yours and its not returning anything

And checked config and the propertie is there (<data alias="ShowInFooter">1</data>)

@Seb - Thanks again, but still not returning anything? Wondering if its my select statement thats wrong?

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Lee 1130 posts 3088 karma points

Jul 16, 2009 @ 17:47
1
HA HAAAAAAAA

I did it, I did it, I did it... Yes I'm quite pleased with myself - I was right, changed my select slighty and now it works
```
<xsl:for-each select="$currentPage/ancestor-or-self::node/descendant-or-self::node">
```
Really appreciate everyones help, many thanks
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Warren Buckley 2106 posts 4836 karma points MVP ∞ admin hq c-trib

Jul 17, 2009 @ 09:45

0

Glad you got there in the end Lee.

XSLT & XPath does have a learning curve but I think it is worth sticking to, at least until 4.1 when you can use Aaron's Linq2Umbraco instead.

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Struggling With Syntax

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