getting value of external link

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Dinesh 13 posts 33 karma points

Sep 19, 2011 @ 22:28

XSLT

Hi,

I have a property with alias name externalLink. I just want to get it's value in href of anchor tag when its present. This is what I have got so far. But it never gives me the value of externalLink even if it's present.

<xsl:template match="/">

<xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
  <div class="Nav2">
    <a href="{umbraco.library:NiceUrl(@id)}"> 
      <xsl:if test="data[@alias='externalLink']!= ''">
        <xsl:attribute name="href">
          <xsl:value-of select="data[@alias='externalLink']"/>
        </xsl:attribute>   
      </xsl:if>
      <xsl:value-of select="navTitle"/>
    </a>
  </div>
</xsl:for-each>

</xsl:template>

Any help will be appreciated.

Thanks

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Tom Fulton 2030 posts 4998 karma points c-trib

Sep 19, 2011 @ 22:38
1
Hi,

It looks like you are mixing the new and old schemas. Try replacing "data [@alias='externalLink']" with just "externalLink", ie:
```
      <xsl:if test="externalLink!= ''">
        <xsl:attribute name="href">
          <xsl:value-of select="externalLink"/>
        </xsl:attribute>   
      </xsl:if>
```
For more info: our.umbraco.org/wiki/reference/xslt/45-xml-schema

-Tom
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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Sep 19, 2011 @ 22:39

Hi Dinesh,

You're actually doing it right, but the snippet you grabbed for the attribute thing uses the old XML schema (search for it if you want to know about it) - here's how that sample would look:

<div class="Nav2">
    <a href="{umbraco.library:NiceUrl(@id)}">
        <xsl:if test="normalize-space(externalLink)">
            <xsl:attribute name="href">
                <xsl:value-of select="externalLink"/>
            </xsl:attribute>   
        </xsl:if>
        <xsl:value-of select="navTitle"/>
    </a>
</div>

I, however, prefer a slightly different approach, using a match template:

<xsl:template match="/">
...
    <div class="Nav2">
        <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:apply-templates select="externalLink[normalize-space()]" />
            <xsl:value-of select="navTitle"/>
        </a>
    </div>
...
</xsl:template>


<xsl:template match="externalLink">
    <xsl:attribute name="href">
        <xsl:value-of select="."/>
    </xsl:attribute>
</xsl:template>

/Chriztian

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 7x admin c-trib

Sep 19, 2011 @ 22:40

0

Snappy, Tom! :-)

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Dinesh 13 posts 33 karma points

Sep 20, 2011 @ 17:00

0

Tom & Chriztian,

Thanks a lot guys. I am just catching up with XSLT. It works like a charm with your suggestions.

-Dinesh

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